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/ Distance from $(1,1,0)$:
Distance from $(1,1,0)$:
February 22, 2026
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Let’s find $(x, y, z)$ such that its distance to each of the three points is also $\sqrt{2}$:
Distance from $(0,0,0)$:
x^2 + y^2 + z^2 = 2
\Rightarrow x^2 - 2x + 1 + y^2 - 2y + 1 + z^2 = 2
\Rightarrow (x^2 + y^2 + z^2) - 2x - 2y + 2 = 2
\Rightarrow 2 - 2x - 2y + 2 = 2 \Rightarrow -2x - 2y = -2 \Rightarrow x + y = 1
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