In a right triangle, one leg measures 9 cm and the hypotenuse is 15 cm. Find the length of the other leg.
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- The surface area is calculated as \( SA = 2(lw + lh + wh) \).
- Substituting dimensions, \( SA = 2(5 \times 8 + 5 \times 10 + 8 \times 10) = 2(40 + 50 + 80) = 2 \times 170 = 340 \) square cm.
- #### Surface Area: 340 square cm, Volume: 400 cubic cm
- Using the Pythagorean theorem, \( a^2 + b^2 = c^2 \), where \( c \) is the hypotenuse.
- Let \( a = 9 \), and \( c = 15 \). So, \( 9^2 + b^2 = 15^2 \).
- That simplifies to \( 81 + b^2 = 225 \). Subtracting 81 from both sides, \( b^2 = 144 \).
